Răspuns:
[tex]a) \frac{x+2}{3} + \frac{x+13}{3} = \frac{x+2+x+13}{3} =\frac{2x+15}{3} \\b)\frac{3x-2}{4} -\frac{2x-1}{4} = \frac{3x-2-2x-1}{4} = \frac{x-3}{4} \\c)\frac{6ab}{4abc} \frac{10a^{2}bc^{2} }{21ab} = \frac{6ab10a^{2}bc^{2} }{81a^{2} b^{2}c } =\frac{60a^{3}b^{2} c^{2} }{81a^{2} b^{2}c} = \frac{20a}{27}[/tex]
Explicație pas cu pas:
