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Se da proportia x/3=y/4.Aflati valoarea raportului 3x+2y/5y-2x

Răspuns :

Razvanw0wask
[tex]\dfrac{x}{3}=\dfrac{y}{4} \Rightarrow x=\dfrac{3y}{4}\\ \\ \dfrac{3\cdot \dfrac{3y}{4}+2y}{5y-2\cdot\dfrac{3y}{4}}=\dfrac{\dfrac{17y}{4}}{\dfrac{14y}{4}}=\dfrac{17y}{4} \cdot \dfrac{4}{14y}=\dfrac{17}{14}[/tex]
Miky93ask
x/3=y/4=k
x=3k
y=4k

3*3k+2*4k /5*4k- 2*3k=
9k+8k/20k-6k=
9k+2k/5k-6k=
3k+2/5=
3k=-2/5
k=-2/5 *1/3
k=-2/15
 valoarea raportului= -2/15


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