Răspuns :
[tex] \frac{7}{2x + 3} \\ 7 > 2x + 3 \\ 4 > 2x \\ 2 > x \\ x < 2 \\ x \: apartine \: ( - \infty .2)[/tex]
[tex]2x+3 < 7\Rightarrow 2x < 7-3 \Rightarrow 2x < 4\Rightarrow x<\frac{4}{2}\RIghtarrow\\ \\ \Rightarrow x<2 \Rightarrow \boxed{x\in (-\infty, 2)}[/tex]