masa molara=mCa+2*mO+2*mH=40+2*16+2*1=74 g/mol
74 g.....40g Ca......32g O......2 g H
100g.....x=? Ca......y=? O.......z=? H
x=54,05% Ca
y=43,24% O
z=2,7 % H
Neutralizare
Ca(OH)2 + 2HCl-> CaCl2+ 2H2O
Ca(OH)2 + H2SO4 -> CaSO4 + 2H2O
Reactie cu saruri
Ca(OH)2+ 2NaCl-> CaCl2 + 2NaOH
Ca (OH)2 +2KCl -> CaCl2 + 2KOH
Ca(OH)2 +Na2SO4 ->CaSO4+2NaOH
Ca(OH)2 +MgSO4 -> CaSO4 +Mg(OH)2
