1)
a-endoterma
b-mic
c-cedeze
d-slaba
e-H2O
f-rosu-carmin
2)
1-a
HCl = acid tare => Cm = 10la-pH = 10la-3
=> pH = 3
2-c
NaOH = baza tare => Cm = 10la-3 = 10la-pOH
=> pOH = 3, pH + pOH = 14
=> pH = 14-3 = 11
3-c
4-d
3)
H2SO4 + H2O <==> (HSO4)⁻ + H3O⁺
acid baza baza conj. acid conj.
acid H2SO4 baza H2O
(HSO4)⁻ + H2O <==> (SO4)⁻² + H3O⁺
acid baza baza conj. acid conj.
acid (HSO4)⁻ baza H2O
4)
Cm = niu/Vs, Vs = 300 mL = 0,3 L
=> Cm = 0,03/0,3 = 0,1 mol/L = 10la-1
HClO4 = acid tare
=> Cm = 10la-pH = 10la-1 => pH = 1
5)
Kc = [HI]²/[H2]*[I2]
= 10²/4x0,5 = 50