Răspuns:
1)
folosind teorema lui Pitagora
4² = x² + x²
16 = 2x² => x² = 8 => x = √8 => x = 2√2
2)
folosind Pitagora:
3² = y² + 2,5²
9 = y² + 6,25
y² = 9 - 6,25
y² = 2,75
y = √2,75
3)
folosind pitagora
4² = 2² + z²
16 = 4 + z²
z² = 16 - 4
z² = 12
z = √12
z = 2√3
4)
folosind Pitagora
4² = 3² + t²
16 = 9 + t²
t² = 16 - 9
t² = 7
t = √7
5)
[tex] \tan(30) = \frac{u}{3} [/tex]
[tex] \frac{1}{ \sqrt{3} } = \frac{u}{3} [/tex]
[tex]u = \frac{3}{ \sqrt{3} } [/tex]
[tex]u = \sqrt{3} [/tex]
folosind Pitagora:
v² = 3² + u²
v² = 9 + 3
v² = 12
v = √12
v = 2√3
