Fatacurigla79ask
a fost răspuns

b) (-3)^2+10•[(-1)^2012+(-1)^2013+2•(-2+2•3)]

c) (-2) ^199:2^197-10•{-2-2•[(-4) ^7:2^12-2]}
rpd va rooog

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Răspuns :

Nickygeo79ask

Răspuns:

b) (-3)^2+10•[(-1)^2012+(-1)^2013+2•(-2+2•3)]=

9+10* [1 -1 +2*(-2+6)]= 9+10 *(2*4)=9+10*8=9+80=89

c)(-2) ^199:2^197-10•{-2-2•[(-4) ^7:2^12-2]} =

(-2)¹⁹⁹⁻¹⁹⁷-10*{-2-2*[(-2)¹⁴⁻¹²-2]=

(-2)²- 10*{-2-2*[(-2)²-2]=

4-10 * [-2-2* (4-2)]=

4-10*(-2-2*2)= 4-10* (-2-4)= 4-10 *(-6)=4+60=64

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