Răspuns:
Explicație pas cu pas:
[tex]a,bc +b,ca+c,ab=6,66,~~\dfrac{abc}{100}+\dfrac{bca}{100} +\dfrac{cab}{100}=\dfrac{666}{100} ,~~\dfrac{abc+bca+cab}{100}= \dfrac{666}{100} ,~~deci~ abc+bca+cab=666,~100a+10b+c+100b+10c+a+100c+10a+b=666[/tex]
Deci 111a+111b+111c=666, ⇒111·(a+b+c)=666, ⇒a+b+c=6
abc∈{123, 132, 213, 231, 312, 321}
