Răspuns:
[tex]a+b+c=10\\a,bc+ c,ab + b,ca=\dfrac{abc}{100} +\dfrac{cab}{100}+\dfrac{bca}{y}=\dfrac{abc+cab+bca}{100}=[/tex]
[tex]=\dfrac{100a+10b+c+100c+10a+b+100b+10c+a}{100}=\dfrac{111a+111b+111c}{100}=\dfrac{111*(a+b+c)}{100}=\dfrac{111*10}{100}=\dfrac{111}{10}=11,1[/tex]
Explicație pas cu pas:
