Răspuns:
a)x-3>5<=>x>8 x=(8:+infinit)
b)-x+7<x+5<=>-x-x<-7+5<=>-2x<-3<=>x>2/3 x=(2/3;+infinit)
c)2(x-3)+7>3x+1<=>2x-6+7>3x+1<=>2x-3x>6-7+1<=>-x>0<=>x<0
x=(-infinit;0)
