2.
miu H2 = 2 g/mol
54/2 = 27 moli
miu NH3 = 17 g/mol
34/17 = 2 moli
4,48/22,4 = 0,2 moli CO
2,24/22,4 = 0,1 moli SO3
3.
67,2/22,4 = 3 moli HCl
miu.HCl = 36,5 g/mol
=> m = 36,5x3 = 109,5 g HCl
miu.H2S = 2+32 = 34 g/mol
2x34 = 68 g H2S
