Analogie:
(6, 8, 10) - triplet pitagoreic
10 =(5/4)·8
Deci, AB=6, BC=8, S=48
Răspuns:
AC² = AB² + BC²
AC = 5BC/4
inlocuim AC
25BC²/16 = 36 + BC²
25BC² = 576 + 16BC²
25BC² - 16BC² = 576
9BC² = 576
BC² = 576/9
BC² = 64
BC = 8
S(ABCD) = AB×BC = 6×8 = 48
