A) m=ro x V=0,88g/mol x 200=>m=176g benzen
n=m/M=2,2564 moli
Benzen randament=m praactica/M teoretica x 100=> m practica=70 x 2,2564/100=1,57948
C6H5Cl =>m=n x M=177,7g C6H5Cl
B) 2,2564 moli Cl2
V=n x 22,4=50,54 l Cl2
