Calculam masa de naftalina pura care se nitreaza
mC10H8 pur=89,6 x 400/100=358,4g
C10H8+HNO3--->C10H7NO2+H2O
128g............173g
Xg...............387g
X=286,33 naftalina care se transformă teoretic R=Mp/Mt x 100=286,33 x 100/358,4=80%
