[tex]a = {(2 + \sqrt{2}) }^{2} \\ a = 4 + 4 \sqrt{2} + 2 \\ a = 6 + 4 \sqrt{2} \\ \\ b = 7 - \frac{ 12}{ \sqrt{3} } \\ ampificam \: fractia \: cu \: \sqrt{3} \\ b = 7 - \frac{12 \sqrt{3} }{3} \\ b = 7 - 4 \sqrt{3} \\ \\ ma = \frac{a + b}{2} \\ ma = \frac{6 + 4 \sqrt{2} + 7 - 4 \sqrt{3} }{2} \\ ma = \frac{13 + 4 \sqrt{2} - 4 \sqrt{3} }{2} [/tex]
