Răspuns:
M,glucoza= 180g/mol
niu,glucoza= m/M= 144Og/180g/mol=8mol
1mol............................................2mol
C6H12O6----> 2C2H5OH+2CO2
8mol.............................................x= 16mol CO2
1mol.........2mol
CO2+ 2NaOH---> Na2CO3+ H2O
16mol........x
x= niu= 32mol
c,m= niu/V---> V= niu/c= 32/4 l= 8 l
Explicație:
