Roxanapascareanu9ask Roxanapascareanu9ask Matematică a fost răspuns Demonstrati numerele intregi n pentru pare au loc inegalitatile:a) [tex] \frac{1}{5} < \frac{1}{n } < \frac{1}{2} [/tex]b)[tex] \frac{7}{2 } < \frac{n}{2} < \frac{22}{4} [/tex]c)[tex] - \frac{1}{3 } < \frac{n + 2}{6} < \frac{3}{2} [/tex]d)[tex] - \frac{8}{9 } < \frac{2 \times - 1}{18} < - 1.(6)[/tex]