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rezolvati in Z- inecuatile 5(x-1)<0 1+4(x-1)<-7 4(x+2)>sau= -8 2(x+5)+3<-9 5(2+3x)<-5

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[tex]5(x - 1) < 0 \\ x - 1 < 0 \\ x < 1[/tex]

[tex]1 + 4(x - 1) < - 7 \\ 4(x - 1) < - 8 \\ x - 1 < - 2 \\ x < - 1[/tex]

[tex]4(x + 2) \geqslant - 8 \\ x + 2 \geqslant - 2 \\ x \geqslant - 4[/tex]

[tex]2(x + 5) + 3 < - 9 \\ 2(x + 5) < - 12 \\ x + 5 < - 6 \\ x < - 11[/tex]

[tex]5(2 + 3x) < - 5 \\ 2 + 3x < - 1 \\ 3x < - 3 \\ x < - 1[/tex]

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