Răspuns:
x = 0
Explicație pas cu pas:
4ˣ+2ˣ-2 = 0 <=> (2²)ˣ +2ˣ -2 = 0 <=>
2²ˣ +2ˣ -2 =0
Notam 2ˣ = t =>
t² + t -2 =0 =>
t₁,₂ = [-1±√(1+8)]/2 = (-1±3)/2
t₁ = -2 ; t₂ = 1
t₁ = -2 => 2ˣ = -2 => ecuatia nu are solutii deoarece 2ˣ > 0 , ∀ x ∈ R
t₂ = 1 => 2ˣ = 1 <=> 2ˣ = 2⁰ => x = 0
