[tex]x^2-Sx+P = 0\\ \\\left|\begin{aligned}x_1 &= 2-\sqrt{3} \\ x_2 &= 2+\sqrt{3}\end{aligned}\,\,\,\,\right|\left.\begin{aligned}S &= x_1+x_2=2-\sqrt{3}+2+\sqrt{3} = 4\\ P&= x_1\cdot x_2 = (2-\sqrt 3)\cdot (2+\sqrt{3}) = 4-3 = 1 \end{aligned}\,\,\,\,\right|\\ \\ \\\Rightarrow\boxed{x^2-4x+1 = 0}[/tex]
