Răspuns :
doebicei cu modificarea nr. de moli n se modifica P.
P1V = n1RT
10x50 = n10,082(273+10)
=> n1 = 21,55 moli NH3
P2V = (n1-a)RT
=> 21,55-a = P2V/RT
=> 21,55-a = 6x50/0,082(273+10)
=> a = 8,62 moli NH3 extrasa
8,62 moli m moli b moli
NH3 + HCl --> NH4Cl
1 1 1
=> m = 8,62 moli HCl
miu.NH3 = 17 g/mol
=> masa.NH3 = 17x8,62 = 146,54 g NH3
b = 8,62 moli NH4Cl
miu.NH4Cl = 53,5 g/mol
=> masa.NH4Cl = 53,5x8,62 = 461,17 g