[tex](1+3i)x+(2-5i)y=7+i\\x+3ix+2y-5iy=7+i\\(x+2y)+(3x-5y)i=7+i=>\left \{ {{x+2y=7} \atop {3x-5y=1}} \right. \\x=7-2y\\3(7-2y)-5y=1<=>21-6y-5y=1<=>-11y=-20=>y=\frac{20}{11}\\ x=7-2y=7-2*\frac{20}{11}=7-\frac{40}{11}=\frac{77-11}{11}=\frac{66}{11}=6=>x=6[/tex]
