a fost răspuns

se dau: a=3, b=11, c=2. Calculeaza: a+b-c a+b+c b-a-c b+c-a b-a+c (a+b)-(b+c) ​

Răspuns :

Crys157724ask

a=3

b=11

c=2

_______

a+b-c= 3+11-2=14-2=12

a+b+c=3+11+2=14+2=16

b-a-c= 11-3-2=8-2=6

b+c-a= 11+2-3=13-3=10

(a+b)-(b+c)= ( 3+11)-(11+2)= 14-13=1
a+b-c=3+11-2=12
a+b+c=3+11+2=16
b-a-c=11-3-2=6
b+c+a=11+2+3=16
b-a+c=11-3+2=10
(a+b)-(b+c)=(3+11)-(11+2)=14-13=1