Răspuns:
Explicație pas cu pas:sper că te am ajutat ❤️
[tex]x^2-3x+2=0\\a=1;b=-3;c=2\\\Delta=b^2-4ac=(-3)^2-4*1*2=9-8=1\\x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2a}=\frac{-(-3)\pm\sqrt{1}}{2}=\frac{3\pm 1}{2}\\ x_1=\frac{3+ 1}{2}=\frac{4}{2}=2=>x_1=2\\ x_2=\frac{3-1}{2}=\frac{2}{2}=1=>x_2=1[/tex]
