Răspuns:
Sunt concurente daca si numai daca exista [tex]x\in\mathbb{R}[/tex] astfel incat f(x)=g(x)=h(x)
[tex]\frac{4x-1}{3}=\frac{-6x+5}{6}=\frac{2x+6}{9}[/tex]
Luam prima egalitate
[tex]\frac{4x-1}{3}=\frac{-6x+5}{6}[/tex]
6(4x - 1) = 3(-6x + 5)
24x - 6 = -18x + 15
42x = 21
[tex]x=\frac{1}{2} \\ \\ \frac{4x-1}{3}=\frac{1}{3} \\ \\ \frac{2x+6}{9}=\frac{7}{9}[/tex]
Avem f(x) = g(x)[tex]\neq[/tex]h(x), deci nu sunt concurente
