[tex]\it \stackrel\frown{AB}=\dfreec{360^o}{3}=120^o\\ \\ L_{\stackrel\frown{AB}}=\dfrac{2\pi R\cdot120^o}{360^o}=\dfrac{2\pi\cdot12}{3}=2\pi\cdot4=8\pi\ cm^2[/tex]
Răspuns:
ΔAOB echilateral ; m(BC)=360:3=120=m(AB)=m(AC) Larc=πrn/180=π12 x 120/180=8π
Explicație pas cu pas:
