Răspuns:
[tex]\lim_{x \to \infty} (\frac{x}{2x+1} ) ^{x} = \lim_{x \to \infty} (\frac{x}{x(2+\frac{1}{x}) } ) ^{x} = lim_{x \to \infty} (\frac{1}{(2+\frac{1}{x}) } ) ^{x} = (\frac{1}{(2+0) } ) ^{infinit} = 0[/tex]
