Răspuns:
Explicație pas cu pas:
[tex]a) \\(\frac{1}{2}+\frac{2}{3}-\frac{1}{4}):\frac{1}{6} =\\ (\frac{6}{12}+\frac{8}{12}-\frac{3}{12}):\frac{1}{6} =\\ \frac{11}{12}:\frac{1}{6} = \frac{11}{12} *6 = \frac{11}{2}\\\\ b) \\(3-\frac{4}{3}):\frac{2}{3}-\frac{1}{5} = \\ (\frac{9}{3}-\frac{4}{3})*\frac{3}{2}-\frac{1}{5}=\\ \frac{5}{3}*\frac{3}{2}-\frac{1}{5} =\\\frac{5}{2}-\frac{1}{5}=\frac{25}{10}-\frac{2}{10}=\frac{23}{10}[/tex]
