Răspuns:
[tex]\texttt{h}=6\sqrt{2}\:\texttt{cm}[/tex]
Explicație pas cu pas:
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✎ Cerință: Calculați înălțimea triunghiului.
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[tex]A_{\triangle echil.}=\frac{l^{2}\sqrt{3}}{4}\\\\24\sqrt{3}=\frac{l^{2}\sqrt{3}}{4}\\\\l^{2}=\frac{24\sqrt{3}*4}{\sqrt{3}}\\\\l^{2}=^{\sqrt{3})}\frac{96\sqrt{3}}{\sqrt{3}}\\\\l^{2}=\frac{96*\not3}{\not3}\\\\l^{2}=96\implies l=\sqrt{96}=4\sqrt{6}[/tex]
[tex]h_{\triangle echil.}=\frac{l\sqrt{3}}{2}\\\\h=\frac{\not4\sqrt{6}*\sqrt{3}}{\not2}\\\\h=2\sqrt{18}\\\\h=2*3\sqrt{2}\\\\h=6\sqrt{2}\:cm[/tex]
