[tex]\displaystyle\bf\\f)~\left(\frac{2}{9}\right)^5:\left(\frac{~~6^{^{(3}}}{27}\right)^4=\left(\frac{2}{9}\right)^5:\left(\frac{2}{9}\right)^4=\left(\frac{2}{9}\right)^{5-4}=\boxed{\bf\frac{2}{9}}\\\\\\i)~\left(2\frac{1}{3}\right)^{36}:\left[\frac{49}{9}\right]^{17}=\left(\frac{7}{3}\right)^{36}:\left[\left(\frac{7}{3}\right)^2\right]^{17}=\\\\\\=\left(\frac{7}{3}\right)^{36}:\left(\frac{7}{3}\right)^{34}=\left(\frac{7}{3}\right)^{36-34}=\left(\frac{7}{3}\right)^{2}=\frac{7^2}{3^2}=\boxed{\bf\frac{49}{9}}[/tex]
