Răspuns:
Explicație:
- se afla md sol. de NaHCO3
md= c. ms : 100
md= 10 . 500 : 100=50g NaHCO3
xg yg 50g
NaOH + CO2= NaHCO3
40g 44g 84g
x=50.40 : 84=23,8 g NaOH
n=23,8g: 40g/moli=0,6 moli NaOH
y=44.50 : 84=26,19 g CO2
n=26,19 g : 44g/moli=0,59moli CO2
MNaOH=23+16 +1=40------>40g/moli
MCO2=12 +2.16=44------->44g/moli
MNaHCO3=23 +1 +12 +3.16=84------>84g/moli