Răspuns:
[tex]\frac{2y}{2y+x}=\frac{2\frac{x}{3}}{2\frac{x}{3}+x} = \frac{\frac{2x}{3}}{\frac{2x}{3}+3)x} =\frac{\frac{2x}{3}}{\frac{2x}{3}+\frac{3x}{3}} =\frac{\frac{2x}{3}}{\frac{5x}{3}} =\frac{2x}{3}.\frac{3}{5x} =\frac{2}{5}[/tex]
Explicație pas cu pas:
