HCl + NaOH ---> NaCl + H2O
c%=md/ms * 100=>md = ms/c*100
md HCl = 36,5*20/100=7,3 g HCl
md NaOH = 20*20/100=4 g NaOH
HCl este in exces deci solutia are caracter mai acid in solutia finala
36,5 g HCl...........58,5 g NaCl
7,3 g HCl..............x g NaCl x = 11,7 g NaCl