Smeuandreiask
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Densitatea unui corp scade prin incalzire cu 20%.Cu cat la suta a crescut volumul ?

Răspuns :

Danutghenghea1ask
q'=q-20/100*q
q'=80/100*q
q'=5/4*q
V'=[tex] \frac{m}{q'} [/tex]=[tex] \frac{m}{ \frac{5}{4}q } [/tex]=[tex] \frac{5}{4} [/tex]V
[tex] \frac{p}{100} [/tex]V=V'-V
[tex] \frac{p}{100} [/tex]=[tex] \frac{5}{4} [/tex]-1=[tex] \frac{25}{100} [/tex]=25%

Gossipgirlask
- la temperatura t0 vom avea m=ρ0·V0; la t1, t1>t0 avem m=ρ1·V1; 
ρ1=ρ0-20/100*ρ0=80/100*ρ0;
ρ0·V0=ρ1·V1 ⇒ ρ0·V0=((80/100)*ρ0)*V1 ⇒ V1=100/80*V0=1,25V0;
V1-V0=1,25V0-V0=0,25V0=25%V0

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