(2x+1)^2-3(x+2)^2=2(7-4x) 4x^2+1+4x-3(x^2+4+4x)=14-8x 4x^2+1+4x-3x^2-12-12x=14-8x x^2-8x-11=14-8x x^2-25=0 x^2=25 Cazul 1:x=5 Cazul 2:x=-5 Spor la teme :* !
2(x^2+2x+1)-3(x^2+4x+4)=14-8x 2x^2+4x+2-3x^2-12x-12=14-18x -x^2+10x-24=0 x^2-10x+24=0 delta=b^2-4ac x1=-b+radical din delta/2a x2=-b-radical din delta/2a si de aici cred ca te descurci
