Răspuns :
Aducem la acelasi numitor:3
(9x-2+x)/3<=6
10x-2<=18
10x<=20
x<=2
(9x-2+x)/3<=6
10x-2<=18
10x<=20
x<=2
Aducem la acelasi numitor care este 3 si apoi inmultim in diagonala pt a scapa de numitori
3*3x-3( 2-x)≤6
9x-6+3x≤6
9x+3x≤6+6
12x≤12
x≤12/12
x≤1
3*3x-3( 2-x)≤6
9x-6+3x≤6
9x+3x≤6+6
12x≤12
x≤12/12
x≤1