CloKoRoask
a fost răspuns

Rezolvati in Z ecuatiile:

[tex] \sqrt{18} x - \sqrt{50} =0[/tex]

[tex] \sqrt{45} x+ } \sqrt{180} =0[/tex]
 
Rezolvati in Q ecuatiile:

[tex]3x- \sqrt{3} =0

2x+9=0

[tex] \frac{4}{5} + \frac{3}{4} x=0[/tex]

[tex] \sqrt{} \frac{45}{16} x- \frac{ \sqrt{5} }{2} =0[/tex]

Va rog sa dati si solutiile..S={...}
si daca nu apartine multimii S=Φ

Multumesc ..dau vot +cel mai bun raspuns+multumesc

Răspuns :

Wolfiiask
[tex] 3\sqrt{2}x [/tex]-[tex]5 \sqrt{2} [/tex]=0=>[tex] 3\sqrt{2} x=5 \sqrt{2} => x= \frac{5 \sqrt{2} }{3 \sqrt{2} } = \frac{5}{3} nu apartine lui Z[/tex]
[tex] 3\sqrt{5}x [/tex]+[tex] 6\sqrt{5} [/tex]=0=>[tex]3 \sqrt{5} x=-6 \sqrt{5} =>x= \frac{-6 \sqrt{5} }{3 \sqrt{5} }=-2 apartine Z[/tex]
=>S={-2}
3x=[tex] \sqrt{3} [/tex]=>[tex]x= \frac{ \sqrt{3} }{3} nu apartine Q[/tex] e irational
2x+9=0=> 2x=-9=>x=-9/2=-4,5 apartine Q=>S={-9/2}
[tex] \frac{3x}{4} = \frac{-4}{5} => 3x= \frac{-16}{5} => x= \frac{-16}{15} [/tex]=>S={-16/15}
[tex] \frac{3 \sqrt{5} }{4} x= \frac{ \sqrt{5} }{2} =>x= \frac{ \sqrt{5}}{2} * \frac{4}{3 \sqrt{5} } = \frac{4}{6} = \frac{2}{3} [/tex] apartine Q=> S={2/3}


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