Răspuns :
M NaOh=11+16+1=28 g/mol
m NaOH=10 g
10 gNaOH ....................................16 g O
28g..........................................x
x=16*28/10=44,8
in 40 g NaOH se gasesc 16 g O
in 10 g NaOH se gasesc x g O x = 4 g O
masa molara NaOH = A sodiu + A oxigen + A hidrogen = 23+16+1=40 g/mol
in 10 g NaOH se gasesc x g O x = 4 g O
masa molara NaOH = A sodiu + A oxigen + A hidrogen = 23+16+1=40 g/mol