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Sn=1+3+5+7+.....+(2n+1) calculeaza suma

Răspuns :

Mada97ask
1+3+5+...+(2n+1)=(2*0+1)+(2*1+1)+(2*2+1)+.....+(2*n+1)= 2( 0+1+2+...+n) +n= 2*[n(n+1)]/2 + n = n(n+1)+n= n^2 + 2n

n^2 = n ridicat la puterea a doua

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