Răspuns :
a+b=25⇒ a=25-b
(25-b)*b=100⇔ -b²+25b-100=0
Δ=25²-4*(-1)*(-100)
Δ=625-400=225⇒Δ=√225=+15si-15
b1=(-25-15)/(-2)=20⇒a1=25-20=5
b2=(-25+15)/(-2)=5⇒a2=25-5=20
(25-b)*b=100⇔ -b²+25b-100=0
Δ=25²-4*(-1)*(-100)
Δ=625-400=225⇒Δ=√225=+15si-15
b1=(-25-15)/(-2)=20⇒a1=25-20=5
b2=(-25+15)/(-2)=5⇒a2=25-5=20
DACA nu ai facut ecuatii de gradul 2, descompui numerul 100 in nr prime (2*2*5*5) si iei la rand toate variantele posibile
1.a= 2 :b=50 (f)
2.a=5: b= 20(f)
3.a= 4; b=25(a)
1.a= 2 :b=50 (f)
2.a=5: b= 20(f)
3.a= 4; b=25(a)