2x(3-b)-y(3+b)=0
3xy(8+z)+7a(8-z)=0
3(x+2)+a(x+2)+b(x+2)=(x+2)(3+a+b)=0
x+2=0⇒x=-2
a+b=-3
-4(3-b)-y(3+b)=0
-6y(8+z)+7a(8-z)=0
-12+4b-3y-yb=0
-4(3+b)-y(3+b)=(3+b)(-4-y)=0⇒3+b=0⇒b=-3⇒a⇒0
-4-y=0⇒y=-4
24(8+z)=192+24z⇒24z=192⇒z=8
cred ca aceasta ar putea fi o rezolvare :D
