LORENZOLALAask
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stiind ca x+3+y+4+z+5=12 determinati 2012+x+y+z

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Alex132004ask
x+3+y+4+z+5=12
x+y +z+3+4+5=12
x+y+z+12=12 inseamna ca x+y+z=0,deci 2012+0=2012
Pisicuta02ask
X+3+y+4+z+5=12
x+y+z=12-5-4-3
x+y+z=0
2.012+x+y+z = 2.012+0=2.012

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