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[tex][( \frac{3}{2} + \frac{2}{3}): \sqrt \frac{169}{36}] ^{2012} *[(-2)^{3}]^{5} :( 2^{7})^{2} [/tex]

Răspuns :

=
(13/6:13/6)^2012·(-2)^15:2^14=
(13/6·6/13)^2012·(-2)^1=
1^2012·(-2)=1·(-2)=-2

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