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In ΔMNP ,m(<M)=90 grade,AD_I_NP,D∈(NP).Daca NP=25 cm si DP=16 cm ,Aflati MP,MN,MD
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Răspuns :

Cu teorema catetei
\[tex]\ PM^2=PD\cdot PN\Rightarrow PM=\sqrt{16\cdot25}=4\cdot5=20\ cm[/tex]
Cu teorema inaltimii
[tex]MD^2=PD\cdot DN\Rightarrow MD=\sqrt{16\cdot9}=4\cdot3=12\ cm[/tex]
Cu teorema catetei
[tex]MN^2=PN\cdot DN\Rightarrow MN=\sqrt{25\cdot9}=5\cdot3=15\ cm[/tex]