Ispasgabriel23ask
a fost răspuns

x²-6x+2(x-3)(y+1)+y²+2y+10

Descompuneti in factori

Răspuns :

MFMask
x²-6x+9+y²+2y+1+2(x-3)(y+1)=
(x-3)²+(y+1)²+2(x-3)(y+1)=[(x-3)+(y+1)]²=(x-3+y+1)²=(x+y-2)²

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