Răspuns :
2x-5 face 3x -2-4x face -2x nu sunt sigur da cred cai bn
[tex] ( \frac{2x-5}{3})^{2} - (\frac{2-4x}{2})^{3} =\frac{ 4x^{2}-25 }{6}- \frac{6- 16x^{2} }{6}=\\
\frac{ -12x^{2}-19 }{6}=-2x^{2}-19[/tex]