1)Numarul numerelor naturale de forma [tex] \frac{}{a2b} [/tex] este egal cu .... 2)Se stie ca a+b+c=7.Calculati a)2a+2b+2c b)10a+10b+10c c)a·13+b·13+c·13+21
1) a=1,2,3,4,5,6,7,8,9 b=0,1,2,3,4,5,6,7,8,9 deci avem 9x10=90 de numere 2)a+b+c=7 2a+2b+2c=2x7 2a+2b+2c=14 b) 10a+10b+10c= 10x7 10a+10b+10c=70 c)vei transforma a+b+c in 7 si rezulta 13x7+21=112
