fie ABC = dr(A=90) AM= mediana si Ad = inaltime --->
AM=BM=MC=24:2=12cm.
In ADM=dr(D=90) -----> t.<30---> DM=12;2=6cm. ----> DB= 6cm.----> Ad= Inaltime triunghi eci ----> AD= [tex] \frac{l \sqrt{3} }{2} [/tex] ----> AD=6[tex] \sqrt{3} [/tex]
----> Aria = BC*AD/2= 24*6[tex] \sqrt{3} [/tex]/2=72[tex] \sqrt{3} [/tex]cm[tex] ^{2} [/tex]