a fost răspuns

b=(1+2+3+...+2002)x 3003 la puterea 2005

Răspuns :

(1+2+3+...+2002)x 3003^ 2005=
=(1+2002)x2002:2x3003^2005=2003x1001x3^2005x1001^2005=
=2003x3^2005x1001^2006
b=[tex]b= \frac{2002\cdot2003}{2}\cdot3003^{2005}=1001\cdot2003\cdot3003^{2005} [/tex]=
[tex]2003\cdot3^{2005}\cdot1001^{2006}[/tex]