Răspuns :
[tex] \frac{x-2}{3} = \frac{1}{2} -x[/tex]
2x-4=3-3x
5x=7
x=[tex] \frac{7}{5} [/tex]
2.
Ma=(√2+1+[tex] \frac{1}{ \sqrt{2}+1 } [/tex]):2
rationalizam cu √2-1
(√2+1+√2-1):2=2√2:2=√2
2x-4=3-3x
5x=7
x=[tex] \frac{7}{5} [/tex]
2.
Ma=(√2+1+[tex] \frac{1}{ \sqrt{2}+1 } [/tex]):2
rationalizam cu √2-1
(√2+1+√2-1):2=2√2:2=√2